Q. In an isobaric process, the ratio of heat supplied to the system $(d\theta)$ and work done by the system $(dW)$ for diatomic gas is
A) 1:1
B) 7:2
C) 7:5
D) 5:7
Explanation
(b)
$- \frac{dQ}{dW} = \frac{dQ}{dQ - dE};\lbrack\because dE = dW + dQ: - dW = dQ - dE\rbrack$
$= \frac{nC_{p}dT}{nC_{p}dT - nC_{v}dT} = \frac{C_{p}}{(C_{p} - C_{v})}$
$= \frac{7}{2}$ for diatomic gas
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.