Combustion of glucose takes place according to the equation $C_{6}H_{12}O_{6} + CO_{2} \rightarrow 6CO_{2} + 6H_{2}O;\mathrm{\Delta}H = - 72$kcal. How much energy will be required for the production of 1.6 g of glucose (Molecular mass of glucose = 180)?

Question

Dr. Abubacker · Accepted Answer

(b)
$\mathrm{\Delta}H$ per 1.6 g $= \frac{72 	imes 1.6}{180} = 0.64$ kcal

Q. Combustion of glucose takes place according to the equation $C_{6}H_{12}O_{6} + CO_{2} \rightarrow 6CO_{2} + 6H_{2}O;\mathrm{\Delta}H = - 72$kcal. How much energy will be required for the production of 1.6 g of glucose (Molecular mass of glucose = 180)?

Explanation

Reviewed by Dr. Abubacker

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