For a reaction at $25℃$, enthalpy and entropy changes are $- 11.7 imes 10^{3}J\ mol^{- 1}$ and $- 105\ J\ mol^{- 1}K^{- 1}$ respectively. What is the Gibbs free energy?

Question

For a reaction at $25℃$, enthalpy and entropy changes are $- 11.7 	imes 10^{3}J\ mol^{- 1}$ and $- 105\ J\ mol^{- 1}K^{- 1}$ respectively. What is the Gibbs free energy?

Dr. Abubacker · Accepted Answer

(b)
$\mathrm{\Delta}G = \mathrm{\Delta}H - T\mathrm{\Delta}S,\ T = 25 + 273 = 298\ K$
$= - 11.7 	imes 10^{3} - 298 	imes ( - 105) = 19590\ J = 19.59\ kJ$

Q. For a reaction at $25℃$, enthalpy and entropy changes are $- 11.7 \times 10^{3}J\ mol^{- 1}$ and $- 105\ J\ mol^{- 1}K^{- 1}$ respectively. What is the Gibbs free energy?

Explanation

Reviewed by Dr. Abubacker

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