Equal volumes of monoatomic and diatomic gases at same initial temperature and pressure are mixed. The ratio of specific heats of the mixture $(C_{p}/C_{v})$ will be

Question

Dr. Abubacker · Accepted Answer

(d)
For monoatomic gas, $\gamma_{2} = \frac{C_{p}}{C_{v}} = 1.67$
For diatomic gas, $\gamma_{2} = \frac{C_{p}}{C_{v}} = 1.40$
$	herefore\ \gamma_{1}:\gamma_{2} = \frac{1.67}{1.40} = 1.19:1$

Q. Equal volumes of monoatomic and diatomic gases at same initial temperature and pressure are mixed. The ratio of specific heats of the mixture $(C_{p}/C_{v})$ will be

Explanation

Reviewed by Dr. Abubacker

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