Q. For the reaction $N_{2} + 3H_{2} \rightleftharpoons 2NH_{3}:\mathrm{\Delta}H$ is
A) $\mathrm{\Delta}E - 2RT$
B) $\mathrm{\Delta}E - RT$
C) $\mathrm{\Delta}E + RT$
D) $\mathrm{\Delta}E + 2RT$
Explanation
(a)
$\mathrm{\Delta}H = \mathrm{\Delta}E + \mathrm{\Delta}nRT$
Since, $\mathrm{\Delta}n = 2 - 4 = - 2$
Therefore, $\mathrm{\Delta}H = \mathrm{\Delta}E - 2RT$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.