Q. Two mole of an ideal gas is expanded isothermally and reversibly from 1 L to 10 L at 300 K. The enthalpy change (in kJ) for the process is
A) 11.4
B) $- 11.4$
C) 0
D) 4.8
Explanation
(c)
$\mathrm{\Delta}H = nC_{p}\mathrm{\Delta}T$
The process is isothermal therefore,
$\mathrm{\Delta}G = 0$
$\therefore\ \mathrm{\Delta}H = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.