Q. $\mathrm{\Delta}H{^\circ},(298\ K)$of methanol is given by the chemical equation
A) $CH_{4}(g) + \frac{1}{2}O_{2}(g) \rightarrow CH_{3}OH(g)$
B) $C(graphite) + \frac{1}{2}O_{2}(g) + 2H_{2}(g) \rightarrow CH_{3}OH(l)$
C) $C(diamond) + \frac{1}{2}O_{2}(g) \rightarrow CH_{3}OH(l)$
D) $CO(g) + 2H_{2}(g) \rightarrow CH_{3}OH(l)$
Explanation
The correct answer is Option B: $C(graphite) + \frac{1}{2}O_{2}(g) + 2H_{2}(g) \rightarrow CH_{3}OH(l)$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.