Q. In a calorimeter, the temperature of the calorimeter increases by 6.12 K, the heat capacity of the system is 1.23 kJ/g deg. What is the molar heat of decomposition for $NH_{4}NO_{3}?$
A) $- 7.53\ kJ/mol$
B) $- 398.1\ kJ/mol$
C) $- 16.1\ kJ/mol$
D) $- 602\ kJ/mol$
Explanation
(d)
Molecular weight of $NH_{4}NO_{3} = 80$
$\therefore$ Molar heat of decomposition
$H = ms\mathrm{\Delta}t = 80 + 1.23 \times 6.12$
$= 602$ kJ/mol
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.