Heat of formation of $H_{2}O$ is $- 188$ kJ/mol and $H_{2}O_{2}$ is $- 286$ kJ/mol. The enthalpy change for the reaction $2H_{2}O_{2} \rightarrow 2H_{2}O + O_{2}$ is

Question

Dr. Abubacker · Accepted Answer

(a)
$H_{2} + \frac{1}{2}O_{2} \rightarrow H_{2}O;\ \mathrm{\Delta}H = - 188$ kJ/mol …(i)
$H_{2} + O_{2} \rightarrow H_{2}O_{2};\ \mathrm{\Delta}H = - 286$ kJ/mol …(ii)
By Eq.$(i) - (ii)$
$2H_{2}O_{2} \rightarrow 2H_{2}O + O_{2};$
$\mathrm{\Delta}H = 2( - 188) - 2( - 286) = + 196$ kJ

Q. Heat of formation of $H_{2}O$ is $- 188$ kJ/mol and $H_{2}O_{2}$ is $- 286$ kJ/mol. The enthalpy change for the reaction $2H_{2}O_{2} \rightarrow 2H_{2}O + O_{2}$ is

Explanation

Reviewed by Dr. Abubacker

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