Q. For the isothermal expansion of an ideal gas

A) $E$ and $H$ increases
B) $E$ increases but $H$ decreases
C) $H$ increases but $E$ decreases
D) $E$ and $H$ are unaltered
Explanation

(d)
In isothermal reversible process, ideal gas has constant volume and so, $\mathrm{\Delta}E = 0$ and $\mathrm{\Delta}H = \mathrm{\Delta}E = 0$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.