Q. The entropy values (in $JK^{- 1}\ mol^{- 1}$) of $H_{2}(g) = 130.6\ Cl_{2}(g) = 223.0$ and $HCl(g) = 186.7\ J\ mol^{- 1}K^{- 1}$ at 298 K and 1 atm pressure, the entropy change for the reaction $H_{2}(g) + Cl_{2}(g) \rightarrow 2HCl(g)$ is

A) +540.3
B) +727.3
C) $- 166.9$
D) +19.8
Explanation

(d)
$\mathrm{\Delta}S^{o} = 2S_{HCl}^{o} - (S_{H_{2}}^{o} + S_{Cl_{2}}^{o})$
$= 2 \times 186.7 - (130.6 + 223.0) = 19.8\ JK^{- 1}mol^{- 1}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.