Q. In an irreversible process taking place at constant $T$ and $P$ and in which only pressure volume work is being done, the change in Gibbs free energy $(dG)$ and change in entropy

A) $(dS)_{V,\ E} < 0(dG)_{T,\ P} < 0$
B) $(dS)_{V,\ E} > 0(dG)_{T,\ P} < 0$
C) $(dS)_{V,\ E} > 0(dG)_{T,\ P} = 0$
D) $(dS)_{V,\ E} = 0(dG)_{T,\ P} > 0$
Explanation

(b)
$(dS)_{V,\ E > 0}(dG)_{T,\ P < 0}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.