Q. $C_{diamond} + O_{2} \rightarrow CO_{2};\ \mathrm{\Delta}H = - 395.3\$kJ/mol $C_{graphite} + O_{2} \rightarrow CO_{2};\ \mathrm{\Delta}H = - 393.4\$kJ/mol $C_{graphite} \rightarrow C_{diamond};\ \mathrm{\Delta}H = ?$

A) $- 3.8$
B) $- 1.9$
C) $+ 3.8$
D) $+ 1.9$
Explanation

(d)
By (ii)-(i) C(graphite) $\rightarrow C$ (diamond);
$\mathrm{\Delta}H = - 393.4 - ( - 395.3) = + 1.9$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.