If $C(s) + O_{2}(g) \rightarrow CO_{2}(g);\ \mathrm{\Delta}H = r$ and $CO(g) + \frac{1}{2}O_{2} \rightarrow CO_{2}(g);\ \mathrm{\Delta}H = s$ then, the heat of formation of CO is

Question

Dr. Abubacker · Accepted Answer

(b)
$C(s) + O_{2}(g) \rightarrow CO_{2}(g);\mathrm{\Delta}H = r$ …(i)
$CO(g) + \frac{1}{2}O_{2}(g) \rightarrow CO_{2}(g);\ \mathrm{\Delta}H = s$ …(ii)
$C(s) + \frac{1}{2}O_{2}(g) \rightarrow CO(g);\ \mathrm{\Delta}H = ?$
Subtract Eq. (ii) from Eq. (i)
$C(s) + O_{2}(g) \rightarrow CO_{2}(g);\mathrm{\Delta}H = r$
$CO(g) + \frac{1}{2}O_{2} \rightarrow CO_{2}(g);\ \mathrm{\Delta}H = s$
$\  - \ \ \ \ \ \ \ \ \ \ \ \ \  - \ \ \ \ \ \ \ \ \ \ \  - \ \ \ \ \ \ \ \ \ \ \ \ \  -$
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$C(s) + \frac{1}{2}O_{2}(g) \rightarrow CO(g);\ \mathrm{\Delta}H = r - s$

Q. If $C(s) + O_{2}(g) \rightarrow CO_{2}(g);\ \mathrm{\Delta}H = r$ and $CO(g) + \frac{1}{2}O_{2} \rightarrow CO_{2}(g);\ \mathrm{\Delta}H = s$ then, the heat of formation of CO is

Explanation

Reviewed by Dr. Abubacker

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