When enthalpy and entropy change for a chemical reaction are $- 2.5 imes 10^{3}$ cal and 7.4 cal $\deg^{- 1}{respectively}$ predict the reaction at 298 K is

Question

When enthalpy and entropy change for a chemical reaction are $- 2.5 	imes 10^{3}$ cal and 7.4 cal $\deg^{- 1}{respectively}$ predict the reaction at 298 K is

Dr. Abubacker · Accepted Answer

(a)
When $\mathrm{\Delta}H = - ve,\ \mathrm{\Delta}S = + ve$ and $\mathrm{\Delta}G = - ve$ than reaction is spontaneous

Q. When enthalpy and entropy change for a chemical reaction are $- 2.5 \times 10^{3}$ cal and 7.4 cal $\deg^{- 1}{respectively}$ predict the reaction at 298 K is

Explanation

Reviewed by Dr. Abubacker

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