Q.
A hypothetical reaction $A \rightarrow 2B$, proceeds through following sequence of steps
(i) $A \rightarrow C;\mathrm{\Delta}H = q$ (ii)$C \rightarrow D;\mathrm{\Delta}H = v$
(iii)$\frac{1}{2}D \rightarrow B;\ \mathrm{\Delta}H = x$
Then the heat of reaction i
A) $q - v + 2x$
B) $q + v - 2x$
C) $q + v + 2x$
D) $q + 2v - 2x$
Explanation
(c)
According to Hess’s law, the total heat changes occurring during a chemical reaction are independent of path.
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$\mathrm{\Delta}H = q + V + 2x$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.