An engine operating between $150℃$ and $25℃$ takes 500 J heat from a higher temperature reservoir if there are no frictional losses, then work done by engine is

Question

Dr. Abubacker · Accepted Answer

(d)
$T_{2} = 150 + 273 = 423$ K,
$T_{1} = 25 + 273 = 298$ K
$Q = 500$ K
$\frac{W}{Q} = \frac{T_{2} - T_{1}}{T_{2}}$
$	herefore W = 500\ \left( \frac{423 - 298}{423} ight) = 147.7\ J$

Q. An engine operating between $150℃$ and $25℃$ takes 500 J heat from a higher temperature reservoir if there are no frictional losses, then work done by engine is

Explanation

Reviewed by Dr. Abubacker

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