Q. For the reaction, $H_{2}(g) + I_{2}(g) \longrightarrow 2HI(g)$, the equilibrium constant $K_{p}$ changes with
A) Total pressure
B) Catalyst
C) The amount $H_{2}\ and\ I_{2}$
D) Temperature
Explanation
(d)
$H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g)$
The equilibrium constant $(K_{p})$ changes with the change in temperature.
Note : Variation of equilibrium constant with temperature can be express as:
$\log\frac{K_{2}}{K_{1}} = \frac{\mathrm{\Delta}H}{2.303R}\ \left\lbrack \frac{T_{2} - T_{1}}{T_{1}\mathbf{.}T_{2}} \right\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.