The pH of a buffer solution of 0.1 M $NH_{4}OH$ [$pK_{b} = 5.0$] and 0.01 M $NH_{4}Cl$ is

Question

Dr. Abubacker · Accepted Answer

(c)
$pOH = pK_{b} + \log\frac{\lbrack salt\rbrack}{\lbrack base\rbrack}$
$= 5 + \log\frac{0.01}{0.1}$
$pOH = 5 - 1$
$pOH = 4$
$pH + pOH = 14$
$pH = 14 - pOH$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  = 14 - 4$
$\ \ \ \ \ \ \ \ \ \ \ \ \ pH = 10$

Q. The pH of a buffer solution of 0.1 M $NH_{4}OH$ [$pK_{b} = 5.0$] and 0.01 M $NH_{4}Cl$ is

Explanation

Reviewed by Dr. Abubacker

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