Q. For the following reaction in gaseous phase $CO(g) + \frac{1}{2}O_{2}(g) \longrightarrow CO_{2}(g)\frac{K_{p}}{K_{c}}$ is

A) $(RT)^{\frac{1}{2}}$
B) $(RT)^{\frac{- 1}{2}}$
C) $(RT)$
D) $(RT)^{- 1}$
Explanation

(b)
$K_{p}\ \ \ \ K_{c}(RT)^{n_{g}}$
Where, $n_{g}$ No. of moles of gaseous products – No. of moles of gaseous reactants
$CO(g)\ \ \ \ \ \ \ \ \frac{1}{2}O_{2}(g)\ \ \ \ \ \ \ CO_{2}(g)$
$n_{g}\ \ \ \ \ \ \ 1 - 1.5\ \ \ - \frac{1}{2}$
$\because$ $K_{p}\ \ \ \ K_{c}(RT)^{n_{g}}$
$K_{p}\ \ \ \ K_{c}(RT)^{\frac{- 1}{2}}$
$\frac{K_{p}}{K_{c}}\ \ \ \ (RT)^{\frac{- 1}{2}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Equilibrium MCQs