Q. To a 10 mL of $10^{- 3}\ N\ H_{2}SO_{4}$ solution water has been added to make the total volume of 1 L. Its $pOH$ would be
A) 9
B) 3
C) 12
D) 4
Explanation
(a)
$N_{1}V_{1} = N_{2}V_{2}$
$10^{- 3} \times 10 = N_{2} \times 1000$
$N_{2} = 10^{- 5}$
$pH = 5$
So,$pOH = 14 - 5 = 9$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.