Q. 0.5 M ammonium benzoate is hydrolysed to 0.25 percent. Hence, its hydrolysis constant is
A) $2.5 \times 10^{- 5}$
B) $1.25 \times 10^{- 5}$
C) $3.125 \times 10^{- 6}$
D) $6.25 \times 10^{- 6}$
Explanation
(c)
$K_{h} = Ch^{2}$
$= 0.5 \times \left( \frac{0.25}{100} \right)^{2}$
$= 3.125 \times 10^{- 6}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.