Q. The equilibrium constant $K_{p}$ for the reaction, $H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g)$ is
A) More than one
B) Less than one
C) Equal to $K_{c}$
D) Zero
Explanation
(c)
$H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g)$
We know that, $K_{p} = K_{c}(RT)^{\mathrm{\Delta}n_{g}}$
Here, $\mathrm{\Delta}n_{g} = 2 - 2 = 0$
$\therefore$ $K_{p} = K_{c}(RT)^{0} = K_{c}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.