(c) By using pH=$- \log\sqrt{K_{a}.C}$ $5 = - \log\sqrt{K_{a} \times 1} = - \frac{1}{2}\log K_{a}$ $\log{K_{a} = - 10}$ $K_{a} = 10^{- 10}$ Hence, dissociation constant $\left( K_{a} \right) = 10^{- 10}$.
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.