Q. Hydrogen ion concentration in mol/L in a solution of pH=5.4 will be
A) $3.98 \times 10^{- 6}$
B) $3.68 \times 10^{- 6}$
C) $3.88 \times 10^{6}$
D) $3.98 \times 10^{8}$
Explanation
(a)
pH=5.4
$\therefore$ $\left\lbrack H^{+} \right\rbrack = 10^{- 5.4} = 10^{- 6}.10^{0.6}$
Antilog of 0.6 is $\approx$ 4
$\therefore$ $\left\lbrack H^{+} \right\rbrack = 4 \times 10^{- 6}M$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.