Q. The pH of the solution 5 mL $\frac{M}{5}\ HCl + 10\ mL\ of\ \frac{M}{10}\ NaOH$ is

A) 5
B) 3
C) 7
D) 8
Explanation

(c)
Given, vol. of $HCl = 5\ mL,\ molarity =$M/5
Vol. of $NaOH = 10\ mL,\ molarity =$M/10
Mulliequivalents of $HCl = 5 \times \frac{1}{5} = 1$
Mulliequivalents of $NaOH = 10 \times \frac{1}{10} = 1$
$HCl + NaOH \rightarrow NaCl + H_{2}O$
$\because$ Mulliequivalents of $HCl$ = Mulliequivalents of $NaOH$
$\therefore$ Solution is neutral and pH=7.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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