Q. The solubility product of a sparingly soluble salt $AB$ at room temperature is $1.21 \times 10^{- 6}$. Its molar solubility is
A) $1.21 \times 10^{- 6}$
B) $1.21 \times 10^{- 3}$
C) $1.1 \times 10^{- 4}$
D) $1.1 \times 10^{- 3}$
Explanation
(d)
$AB$ is binary electrolyte,
$s = \sqrt{K_{sp}} = \sqrt{1.21 \times 10^{- 6}} = 1.1 \times 10^{- 3}$ M
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.