Q.
The formation of $SO_{3}$ takes place according to the following reaction, $2SO_{2} + O_{2} \rightleftharpoons 2{SO}_{3},\ \mathrm{\Delta}H = - 45.2\ kcal$. The formation of $SO_{3}$ is favoured by
A) Increase of volume
B) Increase in pressure
C) Increase in temperature
D) Removal of oxygen
Explanation
(b)
In this reaction, $\mathrm{\Delta}H$ is negative, so reaction moves forward by decrease in temperature while value of $\mathrm{\Delta}n_{g} = 2 - 3 = - 1,\ ie,$ negative, so the reaction moves in forward direction by increase in pressure
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.