The solubility product of $BaSO_{4}$is $1.5 imes 10^{- 9}$. The precipitation in a 0.01 M $Ba^{2 +}$ solution will start, on adding $H_{2}SO_{4}$of concentration

Question

The solubility product of $BaSO_{4}$is $1.5 	imes 10^{- 9}$. The precipitation in a 0.01 M $Ba^{2 +}$ solution will start, on adding $H_{2}SO_{4}$of concentration

Dr. Abubacker · Accepted Answer

(c)
$K_{sp}$ of $BaSO_{4} = 1.5 	imes 10^{- 9}:\left\lbrack Ba^{2 +} ightbrack = 0.01\ M$
$\left\lbrack SO_{4}^{2 -} ightbrack = \frac{1.5 	imes 10^{- 9}}{0.01} = 1.5 	imes 10^{- 7}$

Q. The solubility product of $BaSO_{4}$is $1.5 \times 10^{- 9}$. The precipitation in a 0.01 M $Ba^{2 +}$ solution will start, on adding $H_{2}SO_{4}$of concentration

Explanation

Reviewed by Dr. Abubacker

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