Q. For the reaction, $CO(g) + Cl_{2}(g) \rightleftharpoons COCl_{2}(g),\ the\ \frac{K_{p}}{K_{c}}$ is equal to
A) $\frac{1}{RT}$
B) $RT\$
C) $\sqrt{RT}$
D) 1.0
Explanation
(a)
$K_{p} = K_{c}(RT)^{\mathrm{\Delta}n_{\ }}$
$\mathrm{\Delta}n =$ sum of coefficients of gaseous products – that of gaseous reactants
$CO(g) + Cl_{2}(g) \rightarrow COCl_{2}(g)$
$\therefore$ $\mathrm{\Delta}n = 1 - 2 = - 1$
$\therefore$ $K_{p} = K_{c}(RT)^{- 1}$
$\therefore$ $\frac{K_{p}}{K_{c}} = (RT)^{- 1} = \frac{1}{(RT)}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.