Q. The equilibrium constant for the reaction $N_{2} + 3H_{2} \rightleftharpoons 2{NH}_{3}$ is $K$ then the equilibrium constant for the equilibrium, $NH_{3} \rightleftharpoons \frac{1}{2}N_{2} + \frac{3}{2}H_{2}$ is

A) $\frac{1}{K}$
B) $\sqrt{K}$
C) $\frac{1}{K^{2}}$
D) $\frac{1}{\sqrt{K}}$
Explanation

(d)
$K_{1}$ for, $N_{2} + 3H_{2} \rightleftharpoons 2{NH}_{3}$
$K_{2}$ for, $NH_{3} \rightleftharpoons \frac{1}{2}N_{2} + \frac{3}{2}H_{2}$
$\therefore K_{1} \times K_{2} = \frac{\left\lbrack NH_{3} \right\rbrack^{2}}{\left\lbrack N_{2} \right\rbrack\left\lbrack H_{2} \right\rbrack^{3}} \times \frac{\left\lbrack N_{2} \right\rbrack^{1/2}\left\lbrack H_{2} \right\rbrack^{3/2}}{\lbrack NH_{3}\rbrack}$
or, $K_{1} \times K_{2} = \frac{1}{K_{2}}$
$\therefore K_{2} = \frac{1}{\sqrt{K_{1}}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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