Q. Consider the following equilibrium in a closed container $N_{2}O_{4}(g) \rightleftharpoons 2NO_{2}(g)$ At a fixed temperature, the volume of the reaction container is halved. For this change which of the following statement holds true regarding the equilibrium constant $(K_{p})$ and degree of dissociation $(\alpha)$ ?
A) Neither $K_{p}$ nor $\alpha$ changes
B) Both $K_{p}\ and\ \alpha$ changes
C) $K_{p}$ changes but $\alpha$ does not
D) $K_{p}$ does not change but $\alpha$ changes
Explanation
(d)
$N_{2}O_{4}(g) \rightleftharpoons 2NO_{2}(g)$
Given, volume is halved
$\therefore$ Pressure is doubled
$\therefore$ Equilibrium will shift backeard and degree of dissociation $(\alpha)$ will decreases.
$K_{p}$ is constant at constant temperature.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.