Q. The vapour density of $N_{2}O_{4}$at a certain temperature is 30. What is the percentage dissociation of $N_{2}O_{4}$ at this temperature?
A) 46.5%
B) 36.2%
C) 53.3%
D) 64.2%
Explanation
(c)
Degree of dissociation, $\alpha = \frac{D - d}{d}$
$= \frac{46 - 30}{30}$
$= 0.533$ or 53.3%
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.