Q. $A + B \rightleftharpoons C + D$. If finally the concentration of $A$ and $B$ are equal but at equilibrium, concentration of $D$ will be twice of that of $A$ then what will be the equilibrium constant of reaction?
A) 2
B) 4
C) $\frac{2}{3}$
D) $\frac{4}{5}$
Explanation
(b)
$A + B \rightleftharpoons C + D$
$x\ \ \ \ \ \ x\ \ \ \ \ \ \ \ 0\ \ \ \ \ 0$
$2x\ \ \ 2x$
$K_{c} = \frac{\lbrack C\rbrack\lbrack D\rbrack}{\lbrack A\rbrack\lbrack B\rbrack} = \frac{2x \bullet 2x}{x \bullet x} = 4$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.