(c)
$1 \times 10^{- 8}\ M\ HCl$ solution $H_{2}O$ is also present there which also undergoes self ionisation.
$H_{2}O \rightleftharpoons H^{+} + OH^{-}$
$10^{- 7}\ M\ at\ 25℃$
If it is taken simply even without common ion effect, higher concentration must be considered which is $10^{- 7}M\ but\ H^{+}\$from HCl decreases self ionisation which further decreases self ionisation, hence $\left\lbrack H^{+} \right\rbrack$from$\ H_{2}O$.
Hence, net concentration must be smaller than $10^{- 7}$ M.