(a)
$2CO_{2} \rightleftharpoons 2CO\ \ \ \ \ \ \ + \ \ \ \ O_{2}$
At equili. 0.6 atm 0.4 atm 0.2 atm
$\therefore$ $K_{p} = \frac{p_{CO}^{2} \times p_{O_{2}}}{{p_{CO}^{2}}_{2}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{(0.4)^{2}(0.2)}{(0.6)^{2}} = 0.088$