(d)
$\because$ $pH = pK_{a} + \log\frac{\lbrack salt\rbrack}{\lbrack acid\rbrack}$
or $5.8 = 4.8 + \log\frac{\lbrack salt\rbrack}{\lbrack acid\rbrack}$
or $\log\frac{\lbrack salt\rbrack}{\lbrack acid\rbrack} = 1.0$
$\frac{\lbrack salt\rbrack}{\lbrack acid\rbrack} = anti - \log{1.0 = 10}$
$\therefore$ $\frac{\lbrack acid\rbrack}{\lbrack salt\rbrack} = \frac{1}{10} = 0.1$