Q. A precipitate of $AgCl$ is formed when equal volumes of the following are mixed [$K_{sp}for\ AgCl = 10^{- 10}$]
A) $10^{- 4}\ M\ AgNO_{3}\ and\ 10^{- 7}M\ HCl$
B) $10^{- 5}M\ AgNO_{3}\ and\ 10^{- 6}M\ HCl$
C) $10^{- 5}M\ AgNO_{3}\ and\ 10^{- 4}\ M\ HCl$
D) $10^{- 6}\ M\ AgNO_{3}\ and\ 10^{- 6}M\ HCl$
Explanation
(c)
A precipitation of $AgCl$ is formed when equal volumes of $10^{- 5}\ M\ AgNO_{3}$ and $10^{- 4}M\ HCl$ are mixed, because ionic product will be $10^{- 9}$ which is greater than $K_{sp}(10^{- 10})$. For the precipitation of an electrolyte, it is necessary that the ionic product must exceed its solubility product.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.