Q. $NH_{4}HS(s) \rightleftharpoons NH_{3}(g) + H_{2}S(g)$ In the above reaction, if the pressure at equilibrium and at 300 K is 100 atm then what will be the equilibrium constant $K_{p}$?
A) 2500 $atm^{2}$
B) $50\ atm^{2}$
C) $100\ atm^{2}$
D) $200\ atm^{2}$
Explanation
(a)
$NH_{4}HS(s) \rightleftharpoons NH_{3}(g) + H_{2}S(g)$
1 0 0
$p$ $p$ At equilibrium
Given,
$p + p = 100\ atm$
$2p = 100\ atm$
$p = 50\ atm$
$K_{p} = {p_{NH}}_{3}.p_{H_{2}S}$
$= 50 \times 50 = 2500atm^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.