Q. Conjugate bade of $H_{2}PO_{4}^{-}$ is
A) $H_{3}PO_{4}$
B) $P_{2}O_{5}$
C) $PO_{4}^{3 -}$
D) $HPO_{4}^{2 -}$
Explanation
(d)
$H_{2}PO_{4}^{-} + H_{2}O \rightarrow H_{3}O^{+}$ $HPO_{4}^{2 -}$
acid conjugated base
$H_{2}PO_{4}^{-}$ gives $HPO_{4}^{2 -}$ (conjugated base) in aqueous solution. It acts as proton donor.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.