Q. For the following reaction in gaseous phase $CO + \frac{1}{2}O_{2} \longrightarrow CO_{2}$ $\frac{K_{c}}{K_{p}}$ is

A) $(RT)^{\frac{1}{2}}$
B) $(RT)^{\frac{- 1}{2}}$
C) $(RT)$
D) $(RT)^{- 1}$
Explanation

(a)
$K_{p} = K_{c}(RT)^{\mathrm{\Delta}n_{g}}$
$\mathrm{\Delta}n_{g} = 1 - 1.5 = - 0.5$
$K_{p} = K_{c}(RT)^{\frac{- 1}{2}} = \frac{K_{c}}{(RT)^{\frac{1}{2}}}$
$\therefore$ $\frac{K_{c}}{K_{p}} = (RT)^{\frac{1}{2}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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