Q. The correct expression for the solubility product of $Ca_{3}\left( PO_{4} \right)_{2}$ is
A) $108\ s^{5}$
B) $27\ s^{5}$
C) $16\ s^{4}$
D) $81\ s^{4}$
Explanation
(a)
$Ca_{3}\left( PO_{4} \right)_{2} = 3Ca^{2 +} + 2PO_{4}^{3 -}$
5 mol/L $3s$ $2s$
$\therefore$ $K_{sp} = \left\lbrack Ca^{2 +} \right\rbrack^{3}\left\lbrack PO_{4}^{3 -} \right\rbrack^{2}$
$= (3s)^{3}(2s)^{2}$
$K_{sp} = 108s^{5}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.