(a) $pH = - \log{\lbrack H^{+}\rbrack}$ $\left\lbrack H^{+} \right\rbrack = 0.0001 = 1 \times 10^{- 4}$ $pH = \ - \log{\ \left\lbrack 1 \times 10^{- 4} \right\rbrack = 4}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.