Q. The pH of millimolar $HCl$ is
A) 1
B) 3
C) 2
D) 4
Explanation
(b)
(i)Millimolar=$10^{- 3}$M
(ii)$pH = - \log{\lbrack H^{+}\rbrack}$
$pH = - \log{\left( 10^{- 3} \right) = 3}$.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.