Q. The pH of an aqueous solution having hydroxide ion concentration as $1 \times 10^{- 5}$ is

A) 5
B) 9
C) 4.5
D) 11
Explanation

(b)
$\left\lbrack OH^{-} \right\rbrack = 1 \times 10^{- 5}$
$pOH = - \log{\lbrack OH^{-}\rbrack}$
$= - \log{\lbrack 1 \times 10^{- 5}\rbrack}$
$pOH$ = 5
$pH + pOH = 14$
$pH = 14 - pOH$
$= 14 - 5$
$pH = 9$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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