Q. Assuming complete dissociation which of the following aqueous solutions will have the same pH value? (i)100 mL of 0.01 M HCl (ii)100 mL of 0.01 M$H_{2}SO_{4}$ (iii)50 mL of 0.01 M HCl (iv)Mixture of 50 mL of 0.02 M $H_{2}SO_{4}$ and 50 mL of 0.02 M $NaOH$

A) (i), (ii)
B) (i), (iii)
C) (ii), (iv)
D) (i), (iv)
Explanation

(d)
Millieq. of 0.01 M $HCl = \frac{0.01 \times 100}{1000} = 1 \times 10^{- 3}$
$\therefore pH = 3$
Millieq. of 0.02 M $H_{2}SO_{4} = \frac{0.04 \times 50}{1000} = 2 \times 10^{- 3}$
Millieq. of 0.02 M $NaOH = \frac{0.02 \times 50}{1000} = 1 \times 10^{- 3}$
Left $\left\lbrack H^{+} \right\rbrack = 2 \times 10^{- 3} - 1 \times 10^{- 3};\ \therefore pH = 3$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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