Q. Solubility of $BaF_{2}$ in a solution of $Ba\left( NO_{3} \right)_{2}$ will be represented by the concentration term
A) $\lbrack Ba^{2 +}\rbrack$
B) $\left\lbrack F^{-} \right\rbrack$
C) $\frac{1}{2}\left\lbrack F^{-} \right\rbrack$
D) $2\left\lbrack NO_{3}^{-} \right\rbrack$
Explanation
(c)
$Ba\left( NO_{3} \right)_{2}$gives$NO_{3}^{-},\ Ba^{2 +}$ ions, hence $Ba^{2 +}$ ion increases. To keep $K_{sp}$ constant, $\lbrack F^{-}\rbrack$ decreases. Thus, it is represented as $\frac{1}{2}\lbrack F^{-}\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.