Q. For the reaction, $2A(g) \rightleftharpoons 3C(g) + D(s)$, the value of $K_{c}$ will be equal to
A) $K_{p}(RT)$
B) $\frac{K_{p}}{RT}$
C) $= K_{p}$
D) None of these
Explanation
(b)
$2A(g) \rightleftharpoons 3C(g) + D(s)$
For this reaction, $\mathrm{\Delta}n_{g} = 3 - 2 = 1$
$\therefore$ $K_{p} = K_{c}(RT)^{1}$
or $K_{c} = \frac{K_{p}}{RT}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.