30 cc of $\frac{M}{3}\ HCl,\ 20\ cc\ of\ \frac{M}{2}\ HNO_{3}\ and\ 40\ cc\ of\ \frac{M}{4}\ NaOH$ solutions are mixed and the volume was made up to 1 $dm^{3}$. The pH of the resulting solution is

Question

Dr. Abubacker · Accepted Answer

(b)
Total milliequivalent of $H^{+}$
$= 30 	imes \frac{1}{3} + 20 	imes \frac{1}{2} = 20$
Total milliequivalent of $OH^{-}$
$= 40 	imes \frac{1}{4} = 10$
Milliequivalent of $H^{+}$ left
= 20-10=10
$	herefore\ \ \ \ \ \ \left\lbrack H^{+} ightbrack = \frac{10}{1000}\ g\ \ \frac{ions}{dm^{3}} = 10^{- 2}$
$	herefore$ pH=2

Q. 30 cc of $\frac{M}{3}\ HCl,\ 20\ cc\ of\ \frac{M}{2}\ HNO_{3}\ and\ 40\ cc\ of\ \frac{M}{4}\ NaOH$ solutions are mixed and the volume was made up to 1 $dm^{3}$. The pH of the resulting solution is

Explanation

Reviewed by Dr. Abubacker

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