The $pK_{a}$of $HCN$ is 9.30. The pH of a solution prepared by mixing 2.5 moles of KCN and 2.5 moles of KCN and 2.5 moles of HCN in water and making up the total volume of 500 mL, is

Question

Dr. Abubacker · Accepted Answer

(a)
$pH = pK_{a} + \log{\frac{\lbrack KCN\rbrack}{\lbrack HCN\rbrack} = 9.3 + \log{\frac{2.5}{2.5} = 9.30}}$

Q. The $pK_{a}$of $HCN$ is 9.30. The pH of a solution prepared by mixing 2.5 moles of KCN and 2.5 moles of KCN and 2.5 moles of HCN in water and making up the total volume of 500 mL, is

Explanation

Reviewed by Dr. Abubacker

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